Optimal. Leaf size=169 \[ -\frac{3 d^2 (c+d x)}{4 f^3 (a \tanh (e+f x)+a)}-\frac{3 d (c+d x)^2}{4 f^2 (a \tanh (e+f x)+a)}-\frac{(c+d x)^3}{2 f (a \tanh (e+f x)+a)}+\frac{3 d (c+d x)^2}{8 a f^2}+\frac{(c+d x)^3}{4 a f}+\frac{(c+d x)^4}{8 a d}-\frac{3 d^3}{8 f^4 (a \tanh (e+f x)+a)}+\frac{3 d^3 x}{8 a f^3} \]
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Rubi [A] time = 0.194709, antiderivative size = 169, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15, Rules used = {3723, 3479, 8} \[ -\frac{3 d^2 (c+d x)}{4 f^3 (a \tanh (e+f x)+a)}-\frac{3 d (c+d x)^2}{4 f^2 (a \tanh (e+f x)+a)}-\frac{(c+d x)^3}{2 f (a \tanh (e+f x)+a)}+\frac{3 d (c+d x)^2}{8 a f^2}+\frac{(c+d x)^3}{4 a f}+\frac{(c+d x)^4}{8 a d}-\frac{3 d^3}{8 f^4 (a \tanh (e+f x)+a)}+\frac{3 d^3 x}{8 a f^3} \]
Antiderivative was successfully verified.
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Rule 3723
Rule 3479
Rule 8
Rubi steps
\begin{align*} \int \frac{(c+d x)^3}{a+a \tanh (e+f x)} \, dx &=\frac{(c+d x)^4}{8 a d}-\frac{(c+d x)^3}{2 f (a+a \tanh (e+f x))}+\frac{(3 d) \int \frac{(c+d x)^2}{a+a \tanh (e+f x)} \, dx}{2 f}\\ &=\frac{(c+d x)^3}{4 a f}+\frac{(c+d x)^4}{8 a d}-\frac{3 d (c+d x)^2}{4 f^2 (a+a \tanh (e+f x))}-\frac{(c+d x)^3}{2 f (a+a \tanh (e+f x))}+\frac{\left (3 d^2\right ) \int \frac{c+d x}{a+a \tanh (e+f x)} \, dx}{2 f^2}\\ &=\frac{3 d (c+d x)^2}{8 a f^2}+\frac{(c+d x)^3}{4 a f}+\frac{(c+d x)^4}{8 a d}-\frac{3 d^2 (c+d x)}{4 f^3 (a+a \tanh (e+f x))}-\frac{3 d (c+d x)^2}{4 f^2 (a+a \tanh (e+f x))}-\frac{(c+d x)^3}{2 f (a+a \tanh (e+f x))}+\frac{\left (3 d^3\right ) \int \frac{1}{a+a \tanh (e+f x)} \, dx}{4 f^3}\\ &=\frac{3 d (c+d x)^2}{8 a f^2}+\frac{(c+d x)^3}{4 a f}+\frac{(c+d x)^4}{8 a d}-\frac{3 d^3}{8 f^4 (a+a \tanh (e+f x))}-\frac{3 d^2 (c+d x)}{4 f^3 (a+a \tanh (e+f x))}-\frac{3 d (c+d x)^2}{4 f^2 (a+a \tanh (e+f x))}-\frac{(c+d x)^3}{2 f (a+a \tanh (e+f x))}+\frac{\left (3 d^3\right ) \int 1 \, dx}{8 a f^3}\\ &=\frac{3 d^3 x}{8 a f^3}+\frac{3 d (c+d x)^2}{8 a f^2}+\frac{(c+d x)^3}{4 a f}+\frac{(c+d x)^4}{8 a d}-\frac{3 d^3}{8 f^4 (a+a \tanh (e+f x))}-\frac{3 d^2 (c+d x)}{4 f^3 (a+a \tanh (e+f x))}-\frac{3 d (c+d x)^2}{4 f^2 (a+a \tanh (e+f x))}-\frac{(c+d x)^3}{2 f (a+a \tanh (e+f x))}\\ \end{align*}
Mathematica [A] time = 0.401029, size = 244, normalized size = 1.44 \[ \frac{\text{sech}(e+f x) (\sinh (f x)+\cosh (f x)) \left (2 f^4 x \left (6 c^2 d x+4 c^3+4 c d^2 x^2+d^3 x^3\right ) (\sinh (e)+\cosh (e))+(\sinh (e)-\cosh (e)) \cosh (2 f x) \left (6 c^2 d f^2 (2 f x+1)+4 c^3 f^3+6 c d^2 f \left (2 f^2 x^2+2 f x+1\right )+d^3 \left (4 f^3 x^3+6 f^2 x^2+6 f x+3\right )\right )+(\cosh (e)-\sinh (e)) \sinh (2 f x) \left (6 c^2 d f^2 (2 f x+1)+4 c^3 f^3+6 c d^2 f \left (2 f^2 x^2+2 f x+1\right )+d^3 \left (4 f^3 x^3+6 f^2 x^2+6 f x+3\right )\right )\right )}{16 a f^4 (\tanh (e+f x)+1)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.046, size = 929, normalized size = 5.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.31936, size = 251, normalized size = 1.49 \begin{align*} \frac{1}{4} \, c^{3}{\left (\frac{2 \,{\left (f x + e\right )}}{a f} - \frac{e^{\left (-2 \, f x - 2 \, e\right )}}{a f}\right )} + \frac{3 \,{\left (2 \, f^{2} x^{2} e^{\left (2 \, e\right )} -{\left (2 \, f x + 1\right )} e^{\left (-2 \, f x\right )}\right )} c^{2} d e^{\left (-2 \, e\right )}}{8 \, a f^{2}} + \frac{{\left (4 \, f^{3} x^{3} e^{\left (2 \, e\right )} - 3 \,{\left (2 \, f^{2} x^{2} + 2 \, f x + 1\right )} e^{\left (-2 \, f x\right )}\right )} c d^{2} e^{\left (-2 \, e\right )}}{8 \, a f^{3}} + \frac{{\left (2 \, f^{4} x^{4} e^{\left (2 \, e\right )} -{\left (4 \, f^{3} x^{3} + 6 \, f^{2} x^{2} + 6 \, f x + 3\right )} e^{\left (-2 \, f x\right )}\right )} d^{3} e^{\left (-2 \, e\right )}}{16 \, a f^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.19526, size = 640, normalized size = 3.79 \begin{align*} \frac{{\left (2 \, d^{3} f^{4} x^{4} - 4 \, c^{3} f^{3} - 6 \, c^{2} d f^{2} - 6 \, c d^{2} f + 4 \,{\left (2 \, c d^{2} f^{4} - d^{3} f^{3}\right )} x^{3} - 3 \, d^{3} + 6 \,{\left (2 \, c^{2} d f^{4} - 2 \, c d^{2} f^{3} - d^{3} f^{2}\right )} x^{2} + 2 \,{\left (4 \, c^{3} f^{4} - 6 \, c^{2} d f^{3} - 6 \, c d^{2} f^{2} - 3 \, d^{3} f\right )} x\right )} \cosh \left (f x + e\right ) +{\left (2 \, d^{3} f^{4} x^{4} + 4 \, c^{3} f^{3} + 6 \, c^{2} d f^{2} + 6 \, c d^{2} f + 4 \,{\left (2 \, c d^{2} f^{4} + d^{3} f^{3}\right )} x^{3} + 3 \, d^{3} + 6 \,{\left (2 \, c^{2} d f^{4} + 2 \, c d^{2} f^{3} + d^{3} f^{2}\right )} x^{2} + 2 \,{\left (4 \, c^{3} f^{4} + 6 \, c^{2} d f^{3} + 6 \, c d^{2} f^{2} + 3 \, d^{3} f\right )} x\right )} \sinh \left (f x + e\right )}{16 \,{\left (a f^{4} \cosh \left (f x + e\right ) + a f^{4} \sinh \left (f x + e\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{c^{3}}{\tanh{\left (e + f x \right )} + 1}\, dx + \int \frac{d^{3} x^{3}}{\tanh{\left (e + f x \right )} + 1}\, dx + \int \frac{3 c d^{2} x^{2}}{\tanh{\left (e + f x \right )} + 1}\, dx + \int \frac{3 c^{2} d x}{\tanh{\left (e + f x \right )} + 1}\, dx}{a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19363, size = 261, normalized size = 1.54 \begin{align*} \frac{{\left (2 \, d^{3} f^{4} x^{4} e^{\left (2 \, f x + 2 \, e\right )} + 8 \, c d^{2} f^{4} x^{3} e^{\left (2 \, f x + 2 \, e\right )} + 12 \, c^{2} d f^{4} x^{2} e^{\left (2 \, f x + 2 \, e\right )} - 4 \, d^{3} f^{3} x^{3} + 8 \, c^{3} f^{4} x e^{\left (2 \, f x + 2 \, e\right )} - 12 \, c d^{2} f^{3} x^{2} - 12 \, c^{2} d f^{3} x - 6 \, d^{3} f^{2} x^{2} - 4 \, c^{3} f^{3} - 12 \, c d^{2} f^{2} x - 6 \, c^{2} d f^{2} - 6 \, d^{3} f x - 6 \, c d^{2} f - 3 \, d^{3}\right )} e^{\left (-2 \, f x - 2 \, e\right )}}{16 \, a f^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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